Logical Reasoning
MCQs — 10 Questions
(+1)
1
ranking
easy
In a queue of girls, the position of Bhawna is 9th from the beginning and 18th from the end. How many total girls are there in that queue?
Answer: B
Total = position from beginning + position from end − 1 (Bhawna is counted twice).
9 + 18 − 1 = 26 girls.
2
embedded-figures
medium
Select a figure from the options which is EXACTLY embedded in the given figure as one of its parts.
Answer: B
The triangle in option B sits against the vertical line in the middle of the big figure, with its point to the right, in exactly the same size and position.
The shapes in A, C and D cannot be traced anywhere in the figure.
3
combinations
easy
How many possible combinations of 1 keyboard and 1 mouse each can be formed from the given keyboards and mouses?
Answer: C
There are 4 keyboards and 5 mice. Each keyboard can be paired with any of the 5 mice.
4 × 5 = 20 combinations.
4
figure-pattern
medium
Select a figure from the options which will complete the given figure pattern.
Answer: B
Diagonally opposite squares match in style: the top-left and bottom-right squares are striped with a red band; the other two are blue.
In each row the second letter is the first letter turned upside down: M → W, so T → ⊥.
The missing square has its striped half at the bottom right, a red band and the letter ⊥, which is option B.
5
lines-curves
easy
Which of the following letter(s) is/are made up of both straight lines and curved lines?
Answer: D
B has a straight upright line and two curves. P has a straight upright line and one curve. J has a straight top and stem and a curved bottom.
All three letters use both straight and curved lines.
6
word-formation
easy
Select the combination of numbers so that the letters are arranged accordingly to form a meaningful English word.
S E H C W A
1 2 3 4 5 6
Answer: D
The letters make the word CASHEW: C (4), A (6), S (1), H (3), E (2), W (5).
So the order is 4, 6, 1, 3, 2, 5.
7
odd-one-out
medium
Select the odd one out.
Answer: C
Use alphabet positions: T (20) − Q (17) = 3, P (16) − M (13) = 3, H (8) − E (5) = 3.
L (12) − J (10) = 2, so LJ is the odd one out.
8
coding-decoding
easy
The codes for some letters are given below.
Letters: N B C H R D E T S
Codes: ↓ # $ • @ & > + *
What will be the code of TREND?
Answer: A
T = +, R = @, E = >, N = ↓, D = &.
TREND = +@>↓&.
9
mirror-images
medium
Select the CORRECT mirror image of the given figure.
Answer: D
In a mirror placed on the right, left and right swap, while top and bottom stay the same.
So the top green triangle moves to the left, the striped parts swap sides, and the shaded quarters of the circle move to the top-right and bottom-left.
Option A is unchanged, B has a cross in the circle, and C does not flip the circle. Option D is correct.
10
calendar
medium
If Aman's sister's birthday falls on 9th day from second Thursday of July 20XX, then what will be the next date after her birthday?
Answer: A
From the calendar, the Thursdays in July are 3rd, 10th, 17th, ... so the second Thursday is 10th July.
The 9th day from 10th July is 10 + 9 = 19th July (her birthday).
The next date after her birthday is 20th July.
Mathematical Reasoning
MCQs — 10 Questions
(+1)
11
factors-multiples
medium
Which of the following gives the LEAST value?
Answer: C
A: The greatest 3-digit number is 999, and its largest factor is 999 itself.
B: 15 + 30 + 45 + 60 + 75 = 225.
C: 6 × 18 + 2 × 25 = 108 + 50 = 158.
The least value is 158, given by C.
12
open-closed-figures
easy
Which of the following is an open figure?
Answer: D
A figure is closed if its boundary starts and ends at the same point with no gaps.
Figure A is closed. Figures B and C have open ends, so they are open figures.
13
fractions
medium
If all the prime digits are removed from the given arrangement, then what fraction of the remaining digits are even?
7 5 2 8 3 9 1 4 6 5 6 3 1 7 9 2
Answer: C
The prime digits are 2, 3, 5 and 7. Removing them leaves 8, 9, 1, 4, 6, 6, 1, 9 (8 digits).
The even ones are 8, 4, 6, 6 (4 digits).
Fraction = 4/8 = 1/2.
14
place-value
hard
Compare and fill the box using >, < or =.
Answer: C
Left: the smallest 5-digit number using 7, 0, 3, 4 (each at least once) with 4 at hundreds is 30407 (3 _ 4 _ _ with the smallest digits 0, 0, 7 in the other places).
Right: the largest such number with 3 at ten thousands is 37740.
30407 < 37740.
15
weight
hard
What is the weight of the jar?
Answer: D
The first scale shows that the jar weighs the same as 11 balls.
The second scale shows that the jar weighs the same as 1 ball + 15 kg 500 g.
So 11 balls = 1 ball + 15 kg 500 g, which means 10 balls = 15500 g and 1 ball = 1550 g.
Jar = 11 × 1550 g = 17050 g.
16
factor-tree
medium
Find the value of P × Q.
Answer: A
Work down the factor tree: 340 = 2 × P, so P = 170.
P = 170 = 2 × 85, and 85 = Q × 17, so Q = 5.
P × Q = 170 × 5 = 850.
17
fractions
medium
The simplest form of shaded fraction of the given figure is ________.
Answer: B
The grid has 16 equal squares.
Fully shaded squares: 4. Half-shaded squares: 4, which make 2 full squares.
Shaded = 4 + 2 = 6 squares, so the fraction is 6/16 = 3/8.
18
picture-equations
medium
How much do the sunglasses cost?
Answer: B
From the second row, 3 bags cost ₹ 630, so 1 bag costs 630 ÷ 3 = ₹ 210.
From the first row, 2 sunglasses + 1 bag = ₹ 510, so 2 sunglasses = 510 − 210 = ₹ 300.
One pair of sunglasses costs 300 ÷ 2 = ₹ 150.
19
pictograph
easy
The given pictograph shows the number of sacks of rice stored in the given five stores.
Find the fraction of number of sacks stored in store T to the number of sacks stored in store S.
Answer: C
T = 4 × 75 = 300 sacks and S = 6 × 75 = 450 sacks.
300/450 = 2/3.
20
pictograph
medium
Use the pictograph from Question 19 (each sack picture represents 75 sacks).
If a vehicle can transport 15 sacks of rice in one trip, then how many trips will it take to transport all the sacks in the five stores?
Answer: D
Total pictures = 7 + 5 + 8 + 6 + 4 = 30, so there are 30 × 75 = 2250 sacks.
Trips = 2250 ÷ 15 = 150.
Everyday Mathematics
MCQs — 10 Questions
(+1)
21
division
easy
Mr. Patel bought 1697 cookies. After giving 8 cookies to each of the 9 children, he packed the rest of the cookies into boxes of 13 each. How many boxes did he pack?
Answer: B
Cookies given away = 8 × 9 = 72.
Left = 1697 − 72 = 1625.
Boxes = 1625 ÷ 13 = 125.
22
capacity
easy
The capacity of a small container is 400 mL and the capacity of a big container is 1500 mL. If Sumit uses 9 small containers and 2 big containers of water to fill up an empty tank, then what is the capacity of the tank?
Answer: B
9 × 400 = 3600 mL and 2 × 1500 = 3000 mL.
3600 + 3000 = 6600 mL = 6 L 600 mL.
23
fractions
medium
Vihaan has 2350 flowers. He used 2/5 of them to make some bouquets and used 720 flowers for decoration. How many flowers will be left with him?
Answer: C
Bouquets: 2/5 × 2350 = 940 flowers.
Left = 2350 − 940 − 720 = 690.
24
time
medium
Mr. Mehta took 8 hours 15 mins to drive from city X to city Y. After 1 hour 10 mins of rest, he took another 3 hours 18 mins to drive from city Y to city Z. He arrived at city Z at 7 : 52 p.m. At what time did he leave city X?
Answer: C
Total time = 8 h 15 min + 1 h 10 min + 3 h 18 min = 12 h 43 min.
7 : 52 p.m. − 12 h = 7 : 52 a.m., then − 43 min = 7 : 09 a.m.
25
length
easy
Yashika bought 17 pieces of ribbon of length 515 cm each. How much total length of ribbon did she buy?
Answer: D
17 × 515 = 8755 cm = 87 m 55 cm.
26
perimeter
medium
The perimeter of Rohan's rectangular painting frame and Priya's square painting frame is same. What is the length of Rohan's rectangular frame?
Answer: A
Perimeter of Priya's square = 4 × 4 = 16 cm.
Rohan's rectangle: 2 × (length + 3) = 16, so length + 3 = 8 and length = 5 cm.
27
rounding
easy
On a particular day, 7593 people attended a football match. Round off the total number of people who attended the football match to the nearest hundreds place.
Answer: D
The tens digit of 7593 is 9 (5 or more), so round the hundreds up: 7593 → 7600.
28
fractions
medium
Prateek sold 375 masks and 640 pairs of gloves in a particular week. Find the fraction of number of masks sold to the total number of items sold in that week.
Answer: C
Total items = 375 + 640 = 1015.
Fraction = 375/1015 = 75/203 (dividing both by 5).
29
lcm
medium
Arjun thinks of a number which is less than 120 and is a common multiple of 10 and 14. If the difference of its digits is 7, then the number is ________.
Answer: D
L.C.M. of 10 and 14 = 70. Common multiples are 70, 140, ... and only 70 is less than 120.
The digits of 70 differ by 7 − 0 = 7.
30
directions
medium
Sneha started from point A and walked 300 m towards South, then 400 m towards East and reached at point B. From point B, she walked 500 m towards North to reach point C and then walked 500 m towards East and reached at point D. What type of figure is made by her movements?
Answer: A
She ends at D, which is far to the east of A, so her path never returns to the starting point.
A path that does not end where it started is an open figure.
Achievers Section
MCQs — 5 Questions
(+2)
31
estimation-lcm
hard
Fill in the blanks and select the CORRECT option.
(i) The estimated difference of 7138 and 4910 when each number is rounded off to the nearest thousands, is __P__.
(ii) When a number X is multiplied by 5 and then the product is divided by 4, the result is 480. Then, the value of X is __Q__.
(iii) The LCM of 5th multiple of 11 and 3rd multiple of 5 is __R__.
Answer: D
(i) 7138 → 7000 and 4910 → 5000, so P = 7000 − 5000 = 2000.
(ii) X × 5 ÷ 4 = 480, so X × 5 = 1920 and X = 384.
(iii) 5 × 11 = 55 and 3 × 5 = 15. L.C.M. of 55 and 15 = 3 × 5 × 11 = 165.
32
symmetry-perimeter
hard
Observe the given figures carefully and select the CORRECT option.
A. The number of lines of symmetry in Fig. (q) is 2.
B. The sum of perimeters of both the figures is 172 cm.
Answer: C
Fig. (q) can be folded along both of its diagonals so that the halves match, so it has 2 lines of symmetry. A is true.
Fig. (p) has 24 square sides on its boundary, each 3 cm: 24 × 3 = 72 cm.
Fig. (q) has 20 square sides on its boundary, each 5 cm: 20 × 5 = 100 cm.
72 + 100 = 172 cm, so B is also true.
33
data-handling
hard
The given table shows the number of children who preferred doing different activities in their free time.
(i) What fraction of total children preferred yoga?
(ii) Find the fraction of number of children who preferred cycling to the number of children who preferred photography.
(iii) What fraction of total children preferred gardening and swimming?
Answer: C
Total = 16 + 10 + 8 + 15 + 11 = 60 children.
(i) 8/60 = 2/15.
(ii) 10/16 = 5/8.
(iii) (15 + 11)/60 = 26/60 = 13/30.
34
money
hard
Solve the following and select the CORRECT option.
(i) Maira bought 4 dresses and 1 blazer. She gave 9 notes of ₹ 500 to the shopkeeper and got ₹ 110 back. If the blazer costs ₹ 730, then find the cost of each dress (cost of each dress is same).
(ii) Mr. Verma earns ₹ 13250 every month. If he spends ₹ 6500 each month and saves the rest, then how much total money will he save in a year?
Answer: B
(i) She paid 9 × 500 − 110 = ₹ 4390. Dresses = 4390 − 730 = ₹ 3660, so each dress = 3660 ÷ 4 = ₹ 915.
(ii) Savings per month = 13250 − 6500 = ₹ 6750. In a year: 6750 × 12 = ₹ 81000.
35
roman-numerals
hard
Read the given statements carefully and state T for true and F for false.
(i) The Roman numeral for the number shown on the given abacus is DCCCXLIII.
(ii) The expanded form of CMLXIX is 900 + 40 + 9.
(iii) The Roman numerals DXCVI, DCCXIV, CMIX are arranged in ascending order.
Answer: A
(i) The abacus shows 8 hundreds, 4 tens and 3 ones = 843 = DCCC + XL + III = DCCCXLIII. True.
(ii) CMLXIX = 900 + 60 + 9 = 969, not 900 + 40 + 9. False.
(iii) DXCVI = 596, DCCXIV = 714, CMIX = 909, so they are in ascending order. True.